Lila flies a drone in the direction of 90° towards Avery. Once she gets to Avery she changes course and flies in the direction of 200° towards Mark. Lila and Avery are 20 feet apart; Mark and Avery are 30 feet apart. How far apart are Mark and Lila?

29.8ft

Step-by-step explanation:

suppose that the angles are measured from an x-axis.

we know that:

Lila and Avery are 20 feet apart.

Mark and Avery are 30 feet apart.

If we locate the position of Lila in the (0, 0)

and we use the relation:

x = r*cos(θ) and y = r*cos(θ)

Then the position of Avery is:

P = (20ft*cos(90°), 20ft*sin(90°)) = (0, 20ft)

and the position of mark will be:

P = (0 + 30ft*cos(200°), 20ft + 30ft*sin(300)) = (-28.2ft, 9.7ft)

And because Lila is at the origin, the distance between Mark and Lila is equal to the module of that vector,

Distance = √((28.2ft)^2 + (9.7ft)^2) = 29.8ft

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15