Use the Divergence Theorem to compute the net outward flux of the field F=<-2x, y,-2z> across the surface S, where S is the boundary of the tetrahedron in the first octant formed by the planex+y+z=2. The net outward flux across the boundary of the tetrahedron is:.

The net outward flux across the boundary of the tetrahedron is: -4

Step-by-step explanation:

Given vector field F = ( -2x, y, - 2 z )

= -2 + 1 -2

= -3

According to divergence theorem;

Flux =

x+y+z = 2;  Octant

x from 0 to 2

y from 0 to 2 -x

z from 0 to 2-x-y

= -4

Thus; The net outward flux across the boundary of the tetrahedron is: -4

3.76%

step-by-step explanation:

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step-by-step explanation: