If a = 7, b = -3 and c = 2, the 2nd degree equation that corresponds to these coefficients is: 2x(x+1) + 5x² - 5x = - 2 2x² + 7x - 5 = 0 3x² -7 = 0 4(x² + 7) - 3x - 7 = 0 None of the above.

2x(x+1) + 5x² - 5x= - 2

Step-by-step explanation:

a=7

b=-3

c=2

2nd degree equation is written as

ax^2+bx+c=0

2x(x+1) + 5x² - 5x= - 2

2x^2+2x+5x^2-5x=-2

Collect like terms

2x^2+5x^2+2x-5x+2=0

7x^2-3x+2=0

a=7, b=-3, c=2

Therefore, the 2nd degree equation that corresponds with the above coefficients is 2x(x+1) + 5x² - 5x= - 2

x/3-10=8

x/3=18

x=48

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet