Jenna constructs the model to represent 3x2 + 11x – 4. An algebra tile configuration. 0 tiles are in the Factor 1 spot. 0 tiles are in the Factor 2 spot. 20 tiles are in the Product spot in 4 columns with 5 rows. First row: 3 + x squared, 1 negative x. The last 4 rows are the same: 3 + x, 1 negative. What factors does Jenna need to model for the sides? (3x + 1) and (x – 4) (3x – 1) and (x + 4) (3x – 2) and (x + 2) (3x + 2) and (x – 2)

the answer is the 2nd one (3x-1) and (x+4)

Step-by-step explanation:

the solution is h=10 because you add 9 to each side of the equation.

step-by-step explanation:

i found the life tables for the year 2012. 

life table of males at age 30. probability of dying between ages x and x+1

total population:  

29–30 . . . . . . . . . . . . 0.001030

30–31 . . . . . . . . . . . . 0.001061

males:  

29–30 . . . . . . . . . . . . 0.001420

30–31 . . . . . . . . . . . . 0.001448

white population

29–30 . . . . . . . . . . . . 0.001005

30–31 . . . . . . . . . . . . 0.001037

white males

29–30 . . . . . . . . . . . . 0.001372

30–31 . . . . . . . . . . . . 0.001399

non hispanic white population

29–30 . . . . . . . . . . . . 0.001083

30–31 . . . . . . . . . . . . 0.001116

non hispanic white males

29–30 . . . . . . . . . . . . 0.001477

30–31 . . . . . . . . . . . . 0.001503

jacob, non hispanic white male. 30 years old.

probability that jacob lives to be 30 years old. 

since the given probabilities are probabilities of dying, i think we simply subtract it from 1 to get the probability of living. we will use the probability of non hispanic white male.

                                          probability of living to be 30 y.o.

29 - 30 : 1 - 0.001477 = 0.998523

30 - 31 : 1 - 0.001503 = 0.998497