PLEASEEE HELP !! in two the three sentences, explain how you would find the line of symmetry for the parabola whose equation is y=x2+4x+16

Axis of symmetry line  is parallel to y- axis

Equation of the parabola ( x - ( -2 ))² =  (y - 12 )  

Step-by-step explanation:

Explanation:-

Given equation is y = x²+4 x+16

                            y =  x²+2 (2 ) x + (2)² - (2)² + 16

                           y   = ( x + 2 )² + 12

                         ( x + 2 )² = y - 12

                        ( x - ( -2 ))² =  (y - 12 )  

                         ( x- h)² = 4 a ( y - k)

            Center (h ,k) = ( -2 , 12)

             Here   4 a  = 1

                           a = 1/4

Focus  S = ( h , K +a) = ( -2 , 12 + 0.25) = ( -2 , 12.25)

Axis of symmetry line  is parallel to y- axis

$9.89

step-by-step explanation:

9.90 = p x .06 x .25 (3/12 changed to a decimal)

9.90 = p x 0.015

9.90 - 0.015 = p

9.89 = p

explanation:

step-by-step explanation: