MegaPhone Design Inc. designs megaphones with sport team stickers on opposite sides of the megaphone. Estimate the percent of the surface area of the megaphone

covered by the stickers. Round to the nearest percent.

*see attachment for the megaphone being referred to here

9%

Step-by-step explanation:

==>Given:

Conical megaphone with the following dimensions:

Slant height (s) = 2.25 ft

Diameter (D) = 1.2 ft (radius r = 0.6 ft)

π = 3.1

Area covered by sticker on one side = area of square = 6 in × 6 in = 0.5 ft × 0.5 ft = 0.25 ft²

==>Required

% of the surface of area of the conical megaphone that is covered by the sticker = area covered by the sticker ÷ surface area of megaphone × 100

==>SOLUTION

Area covered by sticker on both sides = 0.25 ft² + 0.25 ft² = 0.5 ft²

Surface area of the megaphone = surface area of a cone = πrs + πr²

S.A of megaphone = (3.14 × 0.6 × 2.25) + (3.14 × 0.6²)

S.A = 4.239 + 1.1304

S.A = 5.3694 ft²

Therefore, % of the surface of area of the conical megaphone that is covered by the sticker = 0.5 ÷ 5.3694 × 100

= 9.31202741

= 9%

none cuz there are no "following statements" regarding the question

step-by-step explanation:

3,6 and 7.

step-by-step explanation:

a) unit place of 37 is 7

so the unit place of cube of 37 will be

7³= 343=3

the answer is 3.

b) unit place of 56 is 6, so the unit place of cube of 56 will be

6³= 216=6

the answer is 6.

c) unit place of 133 is 3, so the unit place of cube of 133 will be

3³= 27= 7.

the answer is 7.