What is the solution of the system of equations shown below? y = 4x + 4 y
= x^2 - 5x + 18 *

(7, 32) and (2, 12)

Step-by-step explanation:

y = 4x + 4

y = x² - 5x + 18

4x + 4 = x² - 5x + 18

x² - 9x + 14 = 0

14 = (-7)(-2)

-9 = -7 + (-2)

(x - 7)(x - 2)=0

x= 7, x = 2

For x = 7

y = 4x + 4  = 4*7 + 4 = 32

(7, 32)

For x = 2

y = 4x + 4 = 4*2 + 4 = 12

(2, 12)

Check:

y = x² - 5x + 18

(7, 32)

32 = 7² - 5*7 + 18

32= 32 true

(2, 12)

12 = 2² - 5*2 + 18

12 = 12 true

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!

.19875994384

step-by-step explanation:

1699/ 8548