Given that circle Q has a radius of 5 and a center of (1,4), which point lies on the perimeter of circle Q?

(x-1)^2 + (y-4)^2 = 5^2

Step-by-step explanation:

In order to find the points that lie on the perimeter of the circle, you find the  algebraic equation of the circle.

The general equation for a circle is given by:

        (1)

The last is a circle centered at the point (h,k) and with radius r.

In this case you have a circle with a radius of r = 5, and the circle is centered at (1,4). Then, you have:

h = 1

k = 4

r = 5

You replace the values of h, k and r in the equation (1):

All point that lies on the curve of the last equation, are point that lie on the perimeter of the circle

the reason why your question keeps getting deleted because this is not a school related question : )

i will answer your question though.

i never tried church's