Mathematics, 18.06.2020 21:57 Jstylez1789

Five hundred draws are made at random from the box: True or false? (a) The expected value for the percentage of 1’s among the draws is exactly 25%. (b) The expected value for the percentage of 1’s among the draws is around 25%, give or take 2% or so. (c) The percentage of 1’s among the draws will be around 25%, give or take 2% or so. (d) The percentage of 1’s among the draws will be exactly 25%. (e) The percentage of 1’s in the box is exactly 25%. (f) The percentage of 1’s in the box is around 25%, give or take 2% or so.

Answers: 1

Show answers

Answers

Answer from: Emptypockets451

Five hundred draws are made at random from the box:

$[60,000 \ |0|'s \ \ \ 20,000 \ |1|'s]$

True or false?

(a) The expected value for the percentage of 1’s among the draws is exactly 25%.

(b) The expected value for the percentage of 1’s among the draws is around 25%, give or take 2% or so.

(d) The percentage of 1’s among the draws will be exactly 25%.

(e) The percentage of 1’s in the box is exactly 25%.

(f) The percentage of 1’s in the box is around 25%, give or take 2% or so.

(a) True

(b) False

(d) False

(e) True

(f) False

Step-by-step explanation:

From (a);

We can infer that the expected value for the percentage of 1’s among the draws is exactly 25% is true.

Because ; average of the box = $\dfrac{20000}{60000+20000}$

average of the box = $\dfrac{20000}{80000}$

average of the box = 0.25

Thus; the expected value is said to be ; 25%

(b) The expected value for the percentage of 1’s among the draws is around 25%, give or take 2% or so.

Well!, this is false.

Because the expected value for the percentage of 1's among the draws is 25% ,as a result of that there won't be any give and take due to the fact that the expected value involves no probability error.

This is true.

If we determine the standard deviation of the box ; we have :

$SD =\sqrt{\dfrac{20000}{80000}*\dfrac{60000}{80000}} \\ \\ SD= 0.433$

The standard error of the sum can now be calculated as :

= 0.433 ×√500

= 9.682

The standard error of the percentage of 1's is:

$=\dfrac{9.682}{500}*100$

= 1.9364%

≅ 2%

(d) The percentage of 1’s among the draws will be exactly 25%

It is clear and obvious that this is false because if we look at what we have in (c) from above ; we will realize that the percentage of 1's among the draws will be around 25% and not exactly 25%

(e) The percentage of 1’s in the box is exactly 25%.

Yes; this is true. The percentage of 1’s in the box is exactly 25%.

(f) The percentage of 1’s in the box is around 25%, give or take 2% or so.

No; this is false. The percentage of 1’s in the box is exactly 25% and not around 25%, give or take 2% or so.

Answer from: Quest

The density of the cube is 40

Answer from: Quest

sorey ik so sorey i need and need to answer a few

Another question on Mathematics

Mathematics, 21.06.2019 14:00

News cameras take an overhead picture of a crowd at an outdoor event journalist then count the total number of people in the picture and use the sample of estimate the total number of people in the crowd this process is an example of

Answers: 1

Answer

Mathematics, 21.06.2019 20:50

What is the greatest number of parts of a circle that can be formed by cutting the circle with 7 straight cuts? (note: the parts do not have to be equal in size)

Answers: 3

Answer

Mathematics, 21.06.2019 22:20

Atriangle has verticals at b(-3,0), c(2,-1), d(-1,2). which transformation would produce an image with verticals b”(-2,1), c”(3,2), d”(0,-1)?

Answers: 2

Answer

Mathematics, 21.06.2019 22:30

If x-1 and x+3 are the factors of x3+10x2+ax+b find a and b

Answers: 1

Answer

You know the right answer?

Five hundred draws are made at random from the box: True or false? (a) The expected value for the pe...