(03.04) What is the vertex of the graph of y = −4(x + 2)2 + 5? (1 point) (2, 5) (−2, 5) (5, −2) (5, 2)

  (-2, 5)

Step-by-step explanation:

The form you're trying to match is the vertex form of the equation of a parabola:

  y = a(x -h)^2 +k . . . . . . . vertex (h, k)

You have ...

  y = -4(x +2)^2 +5

Comparing forms, you see that a=-4, h=-2, k=5.

Then the vertex (h, k) is (-2, 5).

you can first factor out the n to get n(1+5). we know that 1+5 is 6, so we just have 6n.