Each have four possible answers left parenthesis a, b,c, d right parenthesis, one of which is correct. Assume that you guess the answers to three such questions. a. Use the multiplication rule to find P(CWC), where C denotes a correct answer and W denotes a wrong answer.
b. Beginning with CWC, make a complete list of the different possible arrangements of two correct answers and one wrong answer, then find the probability for each entry in the list. P(CWC)minussee above P(WCC)equals? 0.046875 P(CCW)equals? 0.046875 (Type exact answers.)
c. Based on the preceding results, what is the probability of getting exactly two correct answers when three guesses aremade?

a. P(CWC)=0.046875

b.  P(WCC)=0.046875

    P(CCW)=0.046875

c. P=0.140625

Step-by-step explanation:

By the rule of multiplication there are 64 forms to answer three questions. This is calculated as:

    4 _          *            4               *             4            = 64

1st question      2nd question     3rd question

Because there are 4 options for every question. At the same way, from that 64 options, 3 are CWC and it is calculated as:

    1 _          *            3               *             1            = 3

1st question      2nd question     3rd question

Because there is just one answer that is correct for the first question, there are 3 answers wrong for the second question and there are 1 answer correct for the third question.

So, the probability P(CWC) is equal to:

Then, the complete list of the different possible arrangements of two correct answers and one wrong answer are: CWC, WCC and CCW

Therefore, the probabilities P(WCC) and P(CCW) are calculated as:

Finally, the probability of getting exactly two correct answers is the sum of the probabilities calculated before.

-2

7 - 9 = -2

reversed:

-2 + 9 = 7