to estimate the average monthly rent for 1 bedroom apartments, 13 complexes were randomly selected in Orlando. The mean cost is $970 with a standard deviation of $72. Find a 90% confidence interval for the mean monthly rent of all 1 bedroom apartments.

The 90% confidence interval for the mean monthly rent of all 1 bedroom apartments is between $841.67 and $1098.33

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 13 - 1 = 12

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 12 degrees of freedom(y-axis) and a confidence level of . So we have T = 1.7823

The margin of error is:

M = T*s = 1.7823*72 = 128.33

In which s is the standard deviation of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 970 - 128.33 = $841.67

The upper end of the interval is the sample mean added to M. So it is 970 + 128.33 = $1098.33

The 90% confidence interval for the mean monthly rent of all 1 bedroom apartments is between $841.67 and $1098.33

i leave the calculator work to you.

7. diameter 4 miles, circumference 4π miles

8. radius 0.2 miles, circumference 0.4π miles

[this is a bad problem because the actual radius of a car on the track is less than 0.2 miles so the answer is less than 0.4π miles]

9. radius 6 feet, circumference 12π feet

10. diameter 14 cm, circumference 14π cm

11. diameter 4.8 feet, circumference 4.8π feet

81 seats

step-by-step explanation:

if you multiply 0.65 times 125 then you get 81.5 seats. well since you can't have half of a seat you have to round down and get 81 seats in the no children zones. that leave 44 seats outside of the no children zone.