In a large population, 57 % of the people have been vaccinated. If 3 people are randomly selected, what is the probability that AT LEAST ONE of them has been vaccinated?

0.92

Step-by-step explanation:

Given

of Population is vaccinated

So, Probability of a person being vaccinated is

and simultaneously , probability of not vaccinated is

Now, Probability that atleast one of them has been vaccinated is given by

The probability that AT LEAST ONE of them has been vaccinated

P( X ≥1)  = 0.920493

Step-by-step explanation:

Step(i):-

Given  57 % of the people have been vaccinated

p = 57% =0.57

q = 1-p =1-0.57 = 0.43

n = 3

Step(ii):-

The probability that AT LEAST ONE of them has been vaccinated

P( X ≥1) = P( x =1) + P(x =2)+P(x=3)            

               =  0.316179 + 0.419121 +0.185193

            = 0.920493

Final -

The probability that AT LEAST ONE of them has been vaccinated

P( X ≥1)  = 0.920493

c

step-by-step explanation:

because of the levels

  y= -3x is the required function.

step-by-step explanation:

we have been given a table:

x             y

0             0

1             -3

3             -9

-2             6

we can see that the values of y is -3 times the value of x

hence, the function would be: y= -3x.

put the values of x will give the same y as in the table that means function is satisfying the given table.