At a charity raffle event they are giving out tickets labeled 1 through 10 when people come through the doors. If you are given an even-numbered ticket, you are given a prize at the end of the evening. The table shows the results of 500 guests. What is the relative frequency for the guests who will receive a prize? Ticket Number 1 2 3 4 5 6 7 8 9 10 Frequency 48 42 41 56 67 43 39 41 55 68

Relative frequency for guest who will win the prize:

Relative frequency = 50%

Step-by-step explanation:

Total No. of guest = 500

No. of Guests with even-numbered tickets:

Ticket NO. 2 = 42

Ticket NO. 4 = 56

Ticket NO. 6 = 43

Ticket NO. 8 = 41

Ticket NO. 10 = 68

Total No. of Guest with even-numbered ticket = 42+56+43+41+68

Total No. of Guest with even-numbered ticket = 250

So.

Relative frequency = (frequency of desirable event/ total frequency) · 100

Relative frequency = (250/500)· 100

Relative frequency = 50%

the final function for the graph becomes x-2=-1. before graphing you solve the equation, where x=1. then graph accordingly.   ( on the x-axis, 1 on the line will possess a vertical line.)

step-by-step explanation: