A study determined that only 28% of online youth consider themselves to be very skilled or expert at using the Internet. More
than 1200 online interviews, of Canadian youths aged 12 to 17, were
completed. Results are considered accurate to within + 2.8%, 19
times out of 20.
2. a.
Determine the confidence level for the study:
b. State the margin of error:
c. Determine the confidence interval for the study:
d. Suppose that there are 8 500 youth, between 12 and 17 years old, in a particular city.
State the range of these youth who consider themselves expert at using the Internet.

yes because they have the same amount of green and blur marbles.

step-by-step explanation:

answer:

step-by-step explanation:

here, the total dishes = 10

dishes having meat = 3 ( chicken, meatloaf and hamburger )

thus, the probability of having meat on the chosen dishes = number of dishes having meat / total dishes

=

therefore, the probability of not having meat = 1- the probability of having meat on the chosen dishes

=

=

=

⇒ option b is correct.

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.

my guess is

step-by-step explanation: