Write this trinomial in factored form 4b^2 + 17b + 15

(b + 3)(4b + 5)

Step-by-step explanation:

Given

4b² + 17b + 15

Consider the factors of the product of the b² term and the constant term which sum to give the coefficient of the b- term.

product = 4 × 15 = 60 and sum = 17

The factors are 12 and 5

Use these factors to split the b- term

4b² + 12b + 5b + 15 ( factor the first/second and third/fourth terms )

= 4b(b + 3) + 5(b + 3) ← factor out (b + 3) from each term

= (b + 3)(4b + 5) ← in factored form

6mm^3 or .6cm^3

      216

      /   \

  36     6

  /   \     /

6     6   6

factor trees are nice.