Find parametric equations for the tangent line to the curve with the given parametric equations at the specified point. x = t, y = e−4t, z = 5t − t5; (0, 1, 0) x(t), y(t), z(t) = t,1−4t,5t Illustrate by graphing both the curve and the tangent line on a common screen.

Step-by-step explanation:

At the point (0, 1,0) t = 0

Find the tangent vector:

The tangent vector for all points is

The vector equation of the tangent line is

The parametric equation for this line are

step-by-step explanation:

c.   x=2.4cm

step-by-step explanation:

similar triangles are triangles which have the same shape but not the same size. this means their angle measures are equal but their side lengths are not instead they are proportional. to solve, we will set up a proportion and solve.

a proportion is two equal ratios set equal to each other. we form the ratios by finding corresponding sides (sides which match to each other on both triangles by their position). out ratios will be one side of the small triangle over the corresponding side on the big triangle as shown below:

.

to solve the proportion, we'll cross multiply by multiplying numerator with denominator across the equal sign.