At 9:00 on Saturday morning, two bicyclists heading in opposite directions pass each other on a bicycle path. The bicyclist heading north is riding 4 km/hour faster than the bicyclist heading south. At
10:15, they are 40 km apart. Find the two bicyclists' rates.
northbound bicyclist = 18 km/h; southbound bicyclist = 14 km/h
northbound bicyclist = 19 km/h; southbound bicyclist = 15 km/h
northbound bicyclist = 16 km/h; southbound bicyclist = 10 km/h
northbound bicyclist = 18 km/h; southbound bicyclist = 13 km/h

7.9m and 4.3°

step-by-step explanation:

let east be +x and north be +y, x = distance * cos θ, y = distance * sin θ  

for 3.5 south, y = -3.5  

for 8.2, x = 8.2 * cos 30 and y = 8.2 * sin 30  

for 15 west, x = -15  

total x = 8.2 * cos 30 – 15 ≈ -7.9  

total y = -3.5 + 8.2 * sin 30 = 0.6  

magnitude = [(8.2 * cos 30 – 15)^2 + 0.6^2)]^0.5  

the magnitude is approximately 7.9 m  

tan θ = y/x = 0.6/-7.9  

the angle is approximately 4.3˚ north of west

d.) 48 units

step-by-step explanation:

yeah i know the problem you need. i am taking it right now. the answer is step 3

~mickey

tayeserqp p201311