An aquarium 8 m long, 1 m wide, and 1 m deep is full of water. Find the work needed to pump half of the water out of the aquarium. (Use 9.8 m/s2 for g and the fact that the density of water is 1000 kg/m3.) Show how to approximate the required work by a Riemann sum. (Let x be the height in meters below the top of the tank. Enter xi* as xi.)

9800Joules

Step by step Explanations

Before we can set the integral up, let the upper half the aquarium be divided into horizontal slices for easy calculation

Then we will represent distance from the top of the tank as X and also

2 its thickness as ∆x

We will be working on the horizontal slices , since in the horizontal slices each drop of water in a given slice will be have the same distance from the top of the tank.

Given that An aquarium has;

Length = 8 m long,

Width = 1 m wide,

Dept =1 m deep

And ∆x m,

density of water is 1000 kg/m3

g = 9.8 m/s2

CHECK THE ATTACHMENT FOR DETAILED EXPLANATION

i will take them

step-by-step explanation:

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.