Find sec 0 if 0 is in quadrant IV and sin0=-1/5

sec 0 = 5/(2√6)

Step-by-step explanation:

sin 0 = -1/5

Fourth quadrant Cos positive Rest negative

cos²0 + sin²0 = 1

cos²0 = 1-sin²0

cos²0 = 1 - (1/5)²

cos²0 = 1- 1/25

cos²0 = 24/25

cos0 = ±(2√6)/5

quadrant IV cos is positive.

Therefore cos0 = (2√6)/5

Now, sec0 = 1/cos0

sec0 = 1/{(2√6)/5)}

sec0 = 5/(2√6)

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Hope it helps

dude thats to long figure it

step-by-step explanation:

= 5

step-by-step explanation:

to find the 15th term substitute n = 15 into the nth term formula

= (- 3 × 15 ) + 50 = - 45 + 50 = 5