Show that x^2-8x+20 can be written in the form (x-a)^2+a. Where a is an integer

(x - 4)^2 + 4

Step-by-step explanation:

  x^2 - 8x + 20

= x^2 - 2*4*x + 16 + 4

= x^2 - 2*4*x + 4^2 + 4

= (x - 4)^2 + 4

= (x - a)^2 + a, with a = 4

Hope this helps!

step-by-step explanation:

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can you put the picture up?

step-by-step explanation: