What is the equation of the line that is perpendicular to the given line and passes through the point (3, 4)?
4
(3,4)
2
(-3,2)
(0, 1)
Oy= x + 5
Oy= *x+3
O y = 3x + 2
O y = 3x - 5
5 4 3 2 1
2 3
-2
-3

Option (4). y = 3x - 5

Step-by-step explanation:

Given question is incomplete; here is the complete question.

What is the equation of the line that is perpendicular to the given line and passes through the point (3, 4)?

y = –1/3x + 5

y = –1/3x + 3

y = 3x + 2

y = 3x − 5

Line given in the graph passes through the points (-3, 2) and (0, 1).

Slope of the given line =

                                  m =

                                  m =

Let the equation of a line perpendicular to this line is,

y - y' = m'(x - x') [Given line passes through (x', y')]

By the property of perpendicular lines,

m × m' = -1

() × m' = -1

m' = 3

Equation of the perpendicular line will be,

y - 4 = 3(x - 3)

y - 4 = 3x - 9

y = 3x - 5

Option (4) will be the answer.

49%

step-by-step explanation:

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