Angle BCD is a circumscribed angle of circle A. Angle BCA measures 40°. What is the measure of minor arc BD?

100°

Step-by-step explanation:

From the image attached, line BC and line CD are tangents to circle A. Also, AB and AD are the radius of the circle. The tangent theorem states that the angle between a tangent and the radius is 90°. Therefore:

∠ABC and ∠ADC = 90°.

Given triangle ABC:

∠ABC + ∠BCA + ∠CAB = 180°

∠CAB = 180 - ∠ABC - ∠BCA = 180 - 90 - 40 = 50

∠CAB = 50°

From the two tangent theorem, tangents that meet at the same point have the same length. This means BC = CD, ∠ACD = ∠BCA, ∠CAB = ∠CAD.

arc BD = ∠CAB + ∠CAD = 50 + 50

arc BD = 100°

$79500

step-by-step explanation:

11.2

step-by-step explanation:

when doing tangent the tangent of the angle is equal to the opposite side from the angle over the adjacent side to the angle.

tan43 = x / 12

move 12 over by multiplying each side by 12

12tan43 = x

x = about 11.2