Chocolate chip cookies have a distribution that is approximately normal with a mean of 23.1 chocolate chips per cookie and a standard deviation of 2.9 chocolate chips per cookie. Find Upper P 10 and Upper P 90. How might those values be helpful to the producer of the chocolate chip cookies?

And if we solve for a we got

And for the 90 percentile we can do this:

And if we solve for a we got

The P10 would be 19.388 and the P90 26.812

Step-by-step explanation:

Let X the random variable that represent the chocolate chip cookies of a population, and for this case we know the distribution for X is given by:

Where and

For this part we want to find a value a, such that we satisfy this condition:

  (a)

  (b)

We can find a z score value who that satisfy the condition with 0.10 of the area on the left and 0.90 of the area on the right it's z=-1.28.

Using this value we can do this:

And we can solve for the value of interest

And if we solve for a we got

And for the 90 percentile we can do this:

And if we solve for a we got

The P10 would be 19.388 and the P90 26.812

answer: a.

step-by-step explanation: the answer is a. because, you need to converge the fractions to find a solution.

answer: the answer is one

step-by-step explanation:

pemdas, in this situation there is no parenthesis or exponents so you go to multiplication, 1x1=1, then division 1/1= 1 then addition 1+1=2 then subtraction 2-1=1