Triangle Congruence: SAS Quiz Active
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What is the missing statement in the proof?
The proof that AEFG AJHG is shown
Given: G is the midpoint of HF, EF HJ, and EF HJ.
Prove: AEFG AJHG
O FEG HUG
O GFE GHJ
OEGFJGH
O GEFJHG
H
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Mark this and retum

answer: 48

just remember to use pemdas:

parentheses

expressions

multiplication

division

addition

subtraction

1 x=22.52

2: 65/39=604+39x

65x-39x=604

26x=604

x=604/26

×=23.23

the correct answer is

c. 4

step-by-step explanation:

the given polynomial is

the degree of the polynomial is the highest exponent which is 4.

the -4 is called the leading coefficient.

this polynomial has only one term so it is a monomial.

the correct answer is option c.

3. (5x + 1) - (-10x + 6)

simplify the answer choice. combine like terms. remember to distribute the negative to the terms inside the second parenthesis. also remember that two negatives = one positive, and one of each sign = negative.

- (-10x + 6) = + 10x - 6

simplify. combine like terms:

5x + 1 + 10x - 6

5x + 10x + 1 - 6

15x - 5

∴ it is your answer

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