Given the explicit formula, calculate the first four (4) terms. 1. f(n) = 9+8n
2. f(n)=8(n+1)-13
3. f(n)=65-9n

plz help me out

Step-by-step explanation:

Given the following explicit formula, we are to calculate the first four (4) terms of the sequence.

1)  f(n) = 9+8n

When n = 1

f(1) = 9+8(1)

f(1) = 17

when n = 2

f(2) = 9+8(2)

= 9+16

= 25

When n = 3

f(3) = 9+8(3)

f(3) = 33

when n = 4

f(4) = 9+8(4)

= 41

= 25

The first four terms are 17, 25, 33 and 41

2) f(n) = 8(n+1)-13

When n = 1

f(1) = 8(2)-13

f(1) = 3

when n = 2

f(2) =  8(3)-13

= 24-13

= 11

When n = 3

f(3) =  8(4)-13

f(3) = 32-13

= 19

when n = 4

f(4) =  8(5)-13

= 40-13

= 27

The first four terms are 3, 11, 19 and 27

3) f(n) = 65-9n

When n = 1

f(1) = 65-9(1)

f(1) = 56

when n = 2

f(2) = 65-9(2)

= 65-18

= 47

When n = 3

f(3) = 65-9(3)

f(3) = 65-27

= 38

when n = 4

f(4) = 65-9(4)

= 65-36

= 29

The first four terms are 56, 47, 38 and 29

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step-by-step explanation: