Pythagorean triplet whose one member is 15

Step-by-step explanation:

If

for m > n, then a, b, c make a Pythagorean triplet.

We have the system of equations:

Substitute to the second equation:

Therefore we have:

 it's impossible, because 15 is not an even number.

Let's consider all possible sums of two numbers resulting in 15.

We will check which of the numbers are perfect squares.

1 + 14

2 + 13

3 + 12

4 + 11

5 + 10

6 + 9

7 + 8

(Bold not perfect squares)

There are no two perfect squares among the listed pairs of numbers.

Other:

15, 112, 113

We know the Egyptian triangle with sides of length 3, 4, 5.

By modifying this Pythagorean triplet by multiplying by 3 we get:

(3)(3) = 9; (3)(4) = 12; (3)(5) = 15

By modifying this Pythagorean triplet by multiplying by 5 we get:

(5)(3) = 15; (5)(4) = 20; (5)(5) = 25

answer:  

123455421

step-by-step explanation: easy

21/58.

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