Point P is located at (−2, 7), and point R is located at (1, 0). Find the y value for the point Q that is located two thirds the distance from point P to point R. 4.9 4.7 2.5 2.3

5.1

Step-by-step explanation:

Before we calculate  the y value for the point Q that is located two thirds the distance from point P to point R, we need to get the distance of point p from point R using the formula for calculatingf the distance between two points

D = √(x2-x1)²+(y2-y1)²

Given P(−2, 7), and R(1, 0)

RP = √(1-(-2))²+(0-7)²

RP = √3²+(-7)²

RP = √9+49

RP =√58

To get the y value for point Q that is located two thirds the distance from point P to point R, this will give

PQ = y = 2/3 of √58

= 5.1

the answer is 0.071

good luck! : d

d

step-by-step explanation:

given

y + 3 = - 4(x - 2) ← distribute the parenthesis

y + 3 = - 4x + 8 ( subtract 3 from both sides )

y = - 4x + 5 → d