3 pieces of wood have a total length of 32 m. The second piece is twice the size of the first and the third piece is 2 more meters than triple the first. What are the lengths of the pieces of wood? Please explain througly (problem solving algebraically)

X + Y + Z = 32

X2 = Y

X3 + 2 = Z

X + X2 + X3 + 2 = 32

Make X alone

There is a 2 so we subtract 2 from both sides

X + X2 + X3 = 30

Add the X's up

X + X2 + X3 = X6

X6 = 30

Divide by 6

30 / 6 = 5

You are left with X=5

The first piece of wood has a length of 5

5 x 2 = 10

The second piece has a value of 10

5 x 3 + 2 = 17

The third piece is 17

Hope this helps. If you have any questions you may ask.

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