A box of mass 44 kg is pushed hard enough to set it in motion across a flat surface. The coefficient of kinetic friction between the box and the surface (μk)(μk) is 0.48. What minimum pushing force is needed to keep the box moving at a constant velocity?

answer: the angel abc is 30°,and the abc is a triangle where the angel bac is 90°

so ac is the half of 24=12ft,and from the pythagorean theorem we find ba

ba=√bc^2-ac^2=√576-144=√432=12√3ft

so bac is 12+12√3=12(1+√3)ft

you divide them and then you get the answer i took this class this year

step-by-step explanation:

you first to choose the points and then move from then as the slope you have

16 is the coefficient

hope this