A Ship A Steaming due north at 10km per hour sight at
noon, a second ship B in
direction due east and 1² km
away steaming north east at
SKM per hour - Calculate to the
nearest degrees the bearing
of A from B at 12:15pm?

step-by-step explanation:

i think you should think about the question and not look online.

i dont know if you cant find a way its best to actually add all of them start from 105 tho

step-by-step explanation:

the solution of the equation is 2.23 ⇒ answer b

step-by-step explanation:

* lets revise the meaning of exponential function

- the form of the exponential function is y = ab^x, where a ≠ 0, b > 0 ,  

  b ≠ 1, and x is any real number

- it has a constant base b

- it has a variable exponent x

- to solve an exponential equation, take the log or ln of both sides,  

  and solve for the variable

* lets solve the problem

∵

- the base is 7 and the exponent is x

- insert ㏑ in both sides

∴

- use the rule

∴ x ㏑(7) = ㏑(77)

- to find x divide both sides by ㏑(7)

∴

* the solution of the equation is 2.23 to the nearest 2 decimal places