Which value of b will cause the quadratic equation x2 + bx + 5 = 0 to have two real number solutions? –5 –3 3 4

b = -5

Step-by-step explanation:

You needy to calculate the Discriminant = b² - 4ac

If D is zero there is one real solution,

If D less then zero there are no real solutions

Only if D is bigger then zero, there are two real solutions.

x² - 5x + 5 D > 0 so 2 real solutions

see attachment.

x² - 3x + 5 D < 0 so no real solutions

x² + 3x + 5 D < 0 so no real solutions

x² + 4x + 5 D < 0 so no real solutions

what is the model?

step-by-step explanation:

1. sometimes

2.   never

3   .08c = 7.50+.05c   250 pages

step-by-step explanation:

1.   sometimes

the theoretical probability of rolling a 1 is 1/6.   perhaps you got really lucky and never rolled a 1   in those 60 times.   your experimental probability is 0.   or perhaps you rolled a 1   20 times.   your experimental probability is 20/60 is 1/3.     it really just depends on how you rolled in that experiment.

2.   never

the probability of the event occurring is 1.   that is being 100 % sure it will happen.   that is the maximum amount of confidence we have.

3.   no customer card cost:   .08 times number of pages

customer card cost:   7.50 + .05 times number of pages

we want to find when it costs the same amount, so we will set these equal

let c = number of pages

.08c = 7.50+.05c

subtract .05c from each side

.08c-.05c = 7.5+.05c-.05c

.03c=7.5

divide each side by .03

.03c/.03 = 7.5/03

c =250  

the cost is the same at 250 pages