A submarine traveling 100 km from the shore decended 1/10 km below sea level. Then it ascended about 3/5 km the next it again descended by 9/10 km what is the current position with respect to the sea level what is the horizontal distance of the submarine from sea shore?

Horizontal displacement = 100 km

Position with respect to sea level = -0.4km

Step-by-step explanation:

Let the displacement downwards be negative displacement and displacement upwards be positive.

The horizontal distance from the shore remains constant whereas the displacement from the sea level varies as the submarine moves.

The upward displacement = 3/5 km

Downward displacement = - 1/10 km and - 9/10 km

Total displacement = 3/5km - 1/10 km - 9/10km = - 2/5 km = - 0.4 km

Horizontal distance from the shore = 100km

answer: option a.

step-by-step explanation:

you know that the quadrilateral opqr ( a four sided figure) is inscribed in circle. this means that all its vertices are on the circle.

then, by definition, the opposite angles of the quadrilateral are supplementary, this means that the sum of their measures is 180 degrees.

you can observe in the figure that the angles ∠opq   and the angle ∠orq   are opposite, therefore:

then, can be used to d to calculate the measure of ∠opq