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  5 seconds

Step-by-step explanation:

When the ball returns to its original height, it will be 96 ft from the ground. That means we want to solve for t ...

  h(t) = 96

  96 +80t -16t^2 = 96

  16t(5 -t) = 0 . . . . subtract 96 and factor

This equation is true for t=0 and for t=5.

After 5 seconds, the ball will pass the top of the building on the way down.

x -

median = 1.25

range = 12-14.5

interquartile = q12-q14.5

y -

median = 1

range = 15-17

interquartile = q15-q17