The given line passes through the points (-4, -3) and (4, 1)
What is the equation, in point-slope form, of the line that is
perpendicular to the given line and passes through the
point (-4, 3)?
Oy-3 = -2(x + 4)
4
3
2
(4,1)
Oy-3 = -2(x +4)
Ov-3 = {(x + 4)
Oy-3 = 2(x + 4)
+7
-321
2 3 4
5
X
2
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Mark this and return

y = 2x + 11

Step-by-step explanation:

The first thing we need to do

is to find the slope of the line that passes through the points (-4,-3) and (4,1)

Mathematically, that would be;

m = y2-y1/(x2-x1)

where (x1,y1) = (-4,-3) and (x2,y2) = (4,1)

substituting these. values we have;

m = (1-(-3))/(4-(-4)) = 4/8 = 1/2 or 0.5

Now we are told this line is perpendicular to another line that passes through another point.

We can find the slope of this other line

Since both lines are perpendicular, the product of their slope is -1.

Thus , -0.5 * m = -1

m = -1/-0.5 = 2

So the slope of the other line is 2

Using the point-slope form;

y-y1= m(x-x1)

The point for the other line is (-4,3)

So the equation will be

y-3 = 2(x+4)

y-3 = 2x + 8

y = 2x + 11

i really dont know

step-by-step explanation: