Find sin 2x, cos 2x, and tan 2x if sinx = 5
13
and x terminates in quadrant I.
ala
sin 2x
U
х
cos 2x
=
tan 2x
10

12/13 ; 5/13; 12/5

Step-by-step explanation:

sinx =5/13 =opposite/ hypothenus

By Pythagoras rule the hypothenus side can be obtained as

√ 13^2 -5^2 = √169 -25 = √144 = 12

cos x= adjacent/ hypothenus = 12/13

Now Cos2x= Sinx

And Sin2x = Cosx

Hence ;

Sin2x=12/13

Cos2x =5/13

Tan2x= Sin 2x/ Cos 2x

= 12/13 ÷ 5/13

= 12/13 × 13/5 = 12/5

  y= -3x is the required function.

step-by-step explanation:

we have been given a table:

x             y

0             0

1             -3

3             -9

-2             6

we can see that the values of y is -3 times the value of x

hence, the function would be: y= -3x.

put the values of x will give the same y as in the table that means function is satisfying the given table.

18

step-by-step explanation:

draw the shape and you will see that f and k are actually at adjacent vertices (points of the hexagon that are neighboring).   so find the distance between (1,2) and (4,2).   that is easy since (1,2) and (4,2) is just a vertical distance to count, which is 3.   it is a regular polygon which means all sides are congruent.   you have 6 sides (hexa) so multiply 6 by 3 to receive 18.