The sum of the digits of a two-digit number is 14. If the number formed by reversing the digits is less than the original number by 18. Find the original numbers.

Dear friend my answer for this question is 86.

Step-by-step explanation:Let the two digits of two digit number be, 10s digit x and 1s digit y.

x + y = 14

x = 14 - y…..Eq..1

The nuber formed is 10x + y

If the number formed by reversing the digits is 18 less than the original number, what is the original number

On reversing the digit the number will be 10y + x

10y + x + 18 = (10x + y)

10y + x = 10x + y - 18

10y - y + x - 10x = - 18

9y - 9x = -18…Eq..2

Now substituting the value of x from Eq..1 to Eq..2

9y - 9 (14 - y) = - 18

9y - 126 + 9y = - 18

18y = 126 - 18

18y = 108

y = 108/18

y = 6

Thus 1s digit if the number is 6

Substituting the derived value of y in Eq..1 to derive value of x.

x = 14 - y

x = 14 - 6

x = 8

The 10s digit if two digit number is 8.

The original number formed is 86.

On reversing the digits, the number transform to 68, which is 18 less than original number

Answer the original number is 86.

there is no graph so i cant sorry

step-by-step explanation: