A grocer wants to mix two kinds of candy. One kind sells for $1.80 per pound, and the other sells for $3.00 per pound. He wants to mix a total of 15 pounds and sell it for $1.95 per pound. How many pounds of each kind should he use in the new mix? (Round off the answers to the nearest hundredth.)

13.12 pounds of the candy that sells for $1.80 per pound 1.88 pounds of the candy that sells for $3 per pound should be in the mixture.

Step-by-step explanation:

Let x represent the number of pounds of the candy that sells for $1.80 per pound that should be in the mixture.

Let y represent the number of pounds of the candy that sells for $3.00 per pound that should be in the mixture.

The total pounds of both candies in the mixture is 15. It means that

x + y = 15

Since he wants to sell the mixture for $1.95 per pound, the cost of the mixture per pound would be 1.95(x + y)

The equation would be

1.8x + 3y = 1.95(x + y)- - - - - - - - - - 1

Substituting x = 15 - y into equation 1, it becomes

1.8(15 - y) + 3y = 1.95(15 - y + y)

27 - 1.8y + 3y = 29.25

- 1.8y + 3y = 29.25 + 27

1.2y = 2.25

y = 2.25/1.2

y = 1.88

x = 15 - y = 15 - 1.88

x = 15 - 1.88 = 13.12

f is the midpoint of

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841