A researcher receives 106 containers of oxygen. Of those containers, twenty of them have oxygen that is not ionized and the rest are ionized. Two samples are randomly selected, without replacement, from the lot. i) What is the probability that the second one selected is not ionized given that the first one was ionized

0.1905 = 19.05%

Step-by-step explanation:

We have a total of 106 containers of oxygen, from which:

20 have oxygen not ionized, 86 have oxygen ionized.

If the first one selected is ionized, now we have 20 not ionized and 85 ionized.

So the probability of the second one selected being not ionized is the number of not ionized (20) over the total number of containers (20 + 85):

P = 20 / (20 + 85) = 0.1905 = 19.05%

you'll just earn points here

step-by-step explanation: