In ΔABC, ∠A measures 132° and the values of b and a are 36 and 70, respectively. Find the remaining measurements of the triangle, and round your answers to the nearest tenth. ∠B = 82.2°, ∠C = 62.8°, c = 40.6 ∠B = 82.2°, ∠C = 62.8°, c = 30 ∠B = 22.5°, ∠C = 25.5°, c = 40.6 ∠B = 22.5°, ∠C = 25.5°, c = 30

Step-by-step explanation:

You have an angle and 2 sides given. It just so happens that the angle is across from one of the sides. We can use the Law of Sines to find the missing angle B first.

and cross multiply to get

36 sin(132) = 70 sinB and

and

sinB=.3821887674

In order to find a missing angle you will use the 2nd button on your calculator along with the sin button. When you do that you will see

and then enter the decimal and hit "enter". You will get that the missing angle B measures 22.5 rounded to the nearest tenth.

Now that you have angles A and B, you can find C using the Triangle Angle-Sum Theorem (that says that all the angles of a triangle have to add up to equal 180).

C = 180 - 132 - 22.5 so

C = 25.5 degrees

Now we can use the Law of Sines again with angle A and side A and angle C:

and

and get that side c is 40.6

It is the third option there. Locate the third B and that's where you solution starts.

the two may have that, even a breakdown is probably offered

3030 ur welcome

step-by-step explanation: