A survey showed that 79% of adults need correction (eyeglasses, contacts, surgery, etc.) for their eyesight. If 16 adults are randomly selected, find the probability that no more than 1 of them need correction for their eyesight. Is 1 a significantly low number of adults requiring eyesight
correction?
The probability that no more than 1 of the 16 adults require eyesight correction is
(Round to three decimal places as needed.)

P (X≤1) = 0.000

Step-by-step explanation:

Data given:

p = 79% = 0.79

q = 1 - 0.79 = 0.21

n = 16

P (no more than 1 in 16 adults) = P (X≤1)

P (X≤1) = P (X=0) + P (X=1)

We can find the probability by using binomial functions:

P(X=0) = (16! / 0!(16-0)!) · 0.79⁰ · 0.21¹⁶

Use calculator to solve:

P(X=0) = 0.000000000798

P(X=1) = (16! / 1!(16-1)!) · 0.79¹ · 0.21¹⁵

Use calculator to solve:

P(X=1) = 0.000000034506

P (X≤1) = P (X=0) + P (X=1)

P (X≤1) = 0.000000000798 + 0.000000034506

P (X≤1) = 0.00000003530

P (X≤1) = 0.000

As 1 is a very low number, its probability is very small

d is the answer

step-by-step explanation:

given hc ∥ gd.¯¯¯¯¯¯which statement is true

step-by-step explanation:

∠cbe and ∠deb are same-side interior angles