What are the coordinates of the endpoints of the segment T'V'?
Triangle TVW is dilated according to the rule
D02(x, y)=(x, y) to create the image triangle T'V"W",
which is not shown.
O T'(-3, 6) and V'(0, 3)
O T'(-3, 6) and V'(0, 1)
O T'(-1, 2) and V'(0,3)
O T'(-1, 2) and V'(0, 1)
0 N
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2

The coordinates of the endpoints of the segment T'V are; T'(-3, 6) and V'(0, 3)

According to the question;

The given triangle TVW is dilated according to the rule D (3/4)(x,y)=((3/4)x, (3/4)y) to create the image triangle T'V"W", which is not shown.

From the attached image; the coordinates of endpoints T and V are;

Therefore, the result segment of the dilation according to the rule; D (3/4)(x,y)=((3/4)x, (3/4)y) is;

Read more on triangle dilation;

link

A) T'(-3, 6) and V'(0, 3)

Step-by-step explanation:

In the picture attached, triangle TVW is shown.

Transforming points T and V according to the rule (x,y) -> (3/4x, 3/4y), we get:

T(-4, 8) -> (-4*3/4, 8*3/4) -> (-3, 6) which corresponds to T'

V(0, 4) -> (0*3/4, 4*3/4) -> (0, 3) which corresponds to V'

google dat sis

step-by-step explanation:

1,407.5 hours

step-by-step explanation:

we first convert all the time to hours and then sum them up.

there are 24 hours in 1 day, in 58 days, there are 24 x 58 = 1,392 hours.

there are 60 minutes in 1 hour, thus, 30 minutes will be equivalent to 30 / 60 = 0.5 hours.

therefore, the number of hours it will take mercury to complete a full rotation is 1,392 + 15 + 0.5 = 1,407.5 hours