I don't understand this math problem need help plz!

A' (-4, - 7), B' (-5, -4), C' (-4, -3), D' (-3, -4)

Step-by-step explanation:

When rotating about the origin at an angle of 90° in the counterclockwise direction, the given values of (x, y) are interchanged with y also taking a negative sign. That is ;

(x, y) - - - -> (-y, x)

Therefore, in the question above ;

Translation = (x-2, y+3)

A =(-5, 1) = (-5 - 2, 1 + 3) = (-7, 4) - - -> A' = (-4, - 7)

B =(-2, 2) = (-2 - 2, 2 + 3) =(-4, 5) - - -> B' = (-5, -4)

C =(-1, 1) = (-1 - 2, 1 + 3) = (-3, 4) - - -> C' = (-4, -3)

D =(-2, 0) = (-2 - 2, 0+3) =(-4, 3) - - -> D' = (-3, -4)

i think it's eleven too, don't woosh me here, but according to the "experts" it's 2.

the proof starts from the peano postulates, which define the natural

numbers n. n is the smallest set satisfying these postulates:

  p1.   1 is in n.

  p2.   if x is in n, then its "successor" x' is in n.

  p3.   there is no x such that x' = 1.

  p4.   if x isn't 1, then there is a y in n such that y' = x.

  p5.   if s is a subset of n, 1 is in s, and the implication

      (x in s => x' in s) holds, then s = n.

then you have to define addition recursively:

  def: let a and b be in n. if b = 1, then define a + b = a'

      (using p1 and p2). if b isn't 1, then let c' = b, with c in n

      (using p4), and define a + b = (a + c)'.

then you have to define 2:

  def:   2 = 1'

2 is in n by p1, p2, and the definition of 2.

theorem:   1 + 1 = 2

proof: use the first part of the definition of + with a = b = 1.

      then 1 + 1 = 1' = 2   q.e.d.

note: there is an alternate formulation of the peano postulates which

replaces 1 with 0 in p1, p3, p4, and p5. then you have to change the

definition of addition to this:

  def: let a and b be in n. if b = 0, then define a + b = a.

      if b isn't 0, then let c' = b, with c in n, and define

      a + b = (a + c)'.

you also have to define 1 = 0', and 2 = 1'. then the proof of the

theorem above is a little different:

proof: use the second part of the definition of + first:

      1 + 1 = (1 + 0)'

      now use the first part of the definition of + on the sum in

      parentheses:   1 + 1 = (1)' = 1' = 2   q.e.d.

question: match the eqaution with its graph -8x - 5y = 40

answer: 8 x 5 = 40

x= absiss

y= orderly

so you have a proportional graph

question answered by

(jacemorris04)