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Mathematics, 24.06.2020 18:01 carlo123

The hyperbola with center at (4,5), with vertices at (0,5) and (8,5), with b = 2 (x-4/16)^2-(y-5/4)^2=1

(x-4/4)^2 (7-5\16)^2=1

(y-5/16)^2-(x-4/4)^2=1

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