You can rent time on computers at the local copy center for a $9 setup charge and an additional $150 for every 5 minutes. How much time can be rented for $26? Select the correct choice below and fill in the answer box to complete your choice

A. The independent variable is time (t) in minutes, and the dependent vanable is rental cost (), in dollars. The linear function that models this situation is

(Simplify your answer. Do not include the $ symbol in your answer)

B. The independent variable is rental cost (t), in dollars, and the dependent variable is time (t), in minutes. The linear function that models this situation ist

(Simplify your answer. Do not include the 5 symbol in your answer.)

minutes can be rented for $26

(Round to the nearest minute as needed)

A linear model

reasonable for this situation

(A) The independent variable is time (t) in minutes, and the dependent variable is rental cost (), in dollars. The linear function that models this situation is

R(t) = 30t +8

The time that can be rented for $26 = 1min

Step-by-step explanation:

Based on the information given:

Setup charge on Rent at local copy center = $9

an additional $150 for every 5 minutes. To determine the time that can be rented for $26, let's find the relationship between the rental cost and the time.

For every 5min = $150

For 1 min = $150/5

For t min = 150t/5

Where t = number of minutes of rental time

Rental cost = set up charge + additional cost

Let Rental cost = R(t)

R(t) = 9 + 150t/5

Writing it in form of a linear equation: y = mx + c

R(t) = 150t/5 +9

R(t) = (150/5) ×t + 9

R(t) = 30t + 9

The independent variable is time (t) in minutes, and the dependent variable is rental cost (), in dollars. The linear function that models this situation is

R(t) = 30t + 9

The time that can be rented for $26:

Rental cost = $26

R(t) = 30t +9

26 = 30t +9

26-9 = 30t

17 = 30t

t = 17/30 = 0.57

t is approximately = 1min (nearest minute)

The time that can be rented for $26 = 1min

trapezoid

step-by-step explanation:

first i plotted all my points on a grid graph

i made sure all of them were in the correct quadrant

then i saw it was a trapezoid or a quadrilateral

1/2*qr*rs

step-by-step explanation: