Find the area of the irregula 2 in.
3 in
5 in
A = [ ?
3 in.
2 in.
4 in please explain the answer please thanks very much

Refer to the table below if needed. second quadrant third quadrant fourth quadrant sin(1800- - cos(180° -) tan(180°-e) =- tane cot(1800-0) 10 it to solo 888 sin(180° +c) = - sine cos(180° +) =- cose tan(180° +c) = tane cot(180° +o) = cote sec(180° + c) = - seco csc(180° +2) = - csce sin(360° -) =- sine cos(360° -) = cose tan(360° - e) =- tane cot(360° -) = -cote sec(360° -) = seco csc(360° -) = csco sec(180° -) = csc(180° -) = csca 1991 given that sine = 3/5 and lies in quadrant ii, find the following value. tane

Add the fractions, and simply the result to lowest terms. 2/3 + 2/7= ?

Which word in the sentence below is an interrogative pronoun? who is picking us up from school? whousisfrom