Find the x-intercepts (if any) for the graph of the quadratic function. 6x2 + 12x + 5 = 0 Give your answers in exact form. Show your work

x=−1+1/6√6 or x=−1+−1/6√6

Step-by-step explanation:

Let's solve your equation step-by-step.

6x2+12x+5=0

For this equation: a=6, b=12, c=5

6x2+12x+5=0

Step 1: Use quadratic formula with a=6, b=12, c=5.

x=−b±√b2−4ac/2a

x=−(12)±√(12)2−4(6)(5)/2(6)

x=−12±√24/12

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.