If f(x)= x/2-3 and g(x)=4x^2+x-4 find (f+g) (x)

(f+g) (x)=4x^2+3x/2-7

Step-by-step explanation:

f(x)= x/2-3 and g(x)=4x^2+x-4

(f+g) (x)=?

(f+g) (x)=f(x)+g(x)

(f+g) (x)=x/2-3+4x^2+x-4

combining like terms

(f+g) (x)=4x^2+x/2+x-3-4

(f+g) (x)=4x^2+3x/2-7

hope it helps. Brainliest please

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