What is the quotient of x^2-9x+14/x-7?

A. x+2 B. x-7 C. x-2/x-7 D. x-2

(x - 7)(x - 2)

= x - 2 for x ≠ 7    

     x - 7

Step-by-step explanation:

Please use parentheses to show clearly that you are dividing by (x - 7):

 x^2 - 9x - 14

      or    (x^2 - 9x - 14) ÷ (x - 7)

       x - 7

x^2 - 9x + 14 factors into (x - 7)(x + 2).  After rewriting x^2 - 9x + 14 in factored form, the task of division becomes simpler:

(x - 7)(x - 2)

= x - 2 for x ≠ 7    

     x - 7

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~

its an acute right triangle

step-by-step explanation: