Hi, Please i need help with this question. Workings would be deeply appreciated . A straight line which passes through the point (3,-4) makes intercept 3k and -5k on the x and y axes respectively. Find the value of k

k = ⅕  

Step-by-step explanation:

The slope-intercept equation for a straight line is

y = mx + b, where

m = the slope and

b = the y-intercept

Data:

(3,4)     = a point on the line

(3k,0)   = x-intercept

(0,-5k) = y-intercept

Calculations:

1. Slope

m = (y₂ - y₁)/(x₂ - x₁) = (-5k - 0)/(0 - 3k) = -5/(-3) = ⁵/₃

This makes the equation

y = ⁵/₃x - 5k

2. k

Insert the value of the known point: (3,4)

4 = (⁵/₃)(3) - 5k

4 = 5 - 5k

-1 = -5k

k = ⅕

The figure below shows your graph passing through (3,4) with intercepts 3k and -5k on the x- and y-axes respectively .

what is the approximate angle of acb if abc is 25cm and the length of segment bc is 15

step-by-step explanation: